-20x^2+110x+80=30x-20

Solution for -20x^2+110x+80=30x-20 equation:

-20x^2+110x+80=30x-20

We move all terms to the left:

-20x^2+110x+80-(30x-20)=0

We get rid of parentheses

-20x^2+110x-30x+20+80=0

We add all the numbers together, and all the variables

-20x^2+80x+100=0

a = -20; b = 80; c = +100;
Δ = b2-4ac
Δ = 802-4·(-20)·100
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-120}{2*-20}=\frac{-200}{-40}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+120}{2*-20}=\frac{40}{-40}
=-1
$